28v^2-56v=0

Solution for 28v^2-56v=0 equation:

28v^2-56v=0

a = 28; b = -56; c = 0;
Δ = b2-4ac
Δ = -562-4·28·0
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-56}{2*28}=\frac{0}{56}
=0
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+56}{2*28}=\frac{112}{56}
=2
$